Question 145

If 1.5x = 0.04y, then the value of $$\frac{y^2 - x^2}{y^2 - 2xy + x^2}$$

Solution

Given equation can be resolved as $$\frac{(y-x)\times(y+x)}{(y-x)^{2}}$$
or it will be $$\frac{(y+x)}{(y-x)}$$
or $$\frac{(\frac{(y)}{(x)}+1)}{(\frac{(y)}{(x)}-1)}$$

After putting value of $$\frac{(y)}{(x)}$$ from given equation and solving it

we will get answer as $$\frac{(77)}{(73)} $$

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