The total numbers of males and females in a town is 70,000. If the numberof males is increased by 6% and that of the females is increased by 4%, then the total numbers of males and females in the town would become 73520. Whatis the difference between the numberof males and females in the town, in the beginning?

Let total number of males  = $$x$$

females =$$ 70000 - x$$

According to question $$ (x + \dfrac {6}{100} of x ) + [\dfrac{4}{100} of (70000-x)]  = 73520 $$

$$\Rightarrow \dfrac{106}{100}x + [ (70000-x)\dfrac{104}{100}] = 73520 $$

$$\Rightarrow 106x + (70000\times 104) - 104 = 7352000  $$

$$\Rightarrow 2x= 7352000-7280000$$

$$\Rightarrow 2x= 72000$$

$$\Rightarrow x = 36000 $$ ,females = 70000- 36000 = 34000  

then Difference males and females = 36000-34000 = 2000 Ans