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Question 143
The length of the longest pole that can be placed in a room 16 m long, 8 m wide and 11 m high is:
Solution
The length of the longest pole that can be placed in a room 16 m long, 8 m wide and 11 m high will be along the longest diameter of the cuboid
so we get length of pole as $$\sqrt{\ 16^2+8^2+11^2}=\sqrt{\ 441}\ =21$$
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