Solution
Given : $$a^2+a+1=0$$
Dividing both sides by $$'a'$$, we get
=> $$a+1+\frac{1}{a}=0$$
=> $$a+\frac{1}{a}=-1$$
Squaring both sides, we get :
=> $$(a+\frac{1}{a})^2=(-1)^2$$
=> $$a^2+\frac{1}{a^2}+2(a)(\frac{1}{a})=1$$
=> $$a^2+\frac{1}{a^2}=1-2=-1$$
=> $$a^4+a^2+1=0$$
=> Ans - (A)
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