Question 141

If $$x=cosec\theta-sin\theta$$ and $$y=sec\theta-cos\theta$$, then the value of $$x2y2(x2 + y2 + 3)$$


$$x=cosec\theta - sin\theta=\frac{cos^2\theta}{sin\theta}=cot\theta cos\theta$$
Similarly $$y=tan\theta sin\theta$$
$$xy=sin\theta cos\theta$$
$$x^2+y^2+3=(sec^2\theta +cosec^2\theta )$$
Now putting above values in given equation, and after solving it will be reduced to 1

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