An AC voltage $$V = 20\sin(200\pi t)$$ is applied to a series LCR circuit which drives a current $$I = 10\sin\left(200\pi t + \frac{\pi}{3}\right)$$. The average power dissipated is:

$$V_0=20$$V, $$I_0=10$$A. Phase difference $$\phi=\pi/3$$.

$$P_{avg}=\frac{V_0I_0}{2}\cos\phi=\frac{20\times10}{2}\cos60°=100\times0.5=50$$ W.

The answer is Option (4): 50 W.

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