Question 137

Working 7 hours a day, 18 persons can complete a certain work in 32 days. In how many days would 14 persons complete the same work, working 8 hours a day?

Solution

We know that of M1 man can do W1 work in H1 hours per day and M2 man can do work W2 work H2 hour per day

then $$ \dfrac {M1 D1 H1 }{W1} = \dfrac {M2 D2 H2}{w2}$$

M1 = 18, M2 = 14 , D1 = 32 , H1 = 7, H2 = 8 , W1 = W2

so $$\dfrac{18\times32\times7}{W1}= \dfrac{14\times8\times D2}{W1} $$

$$\Rightarrow D2 = \dfrac{18\times 32 \times 7} {14\times 8}$$

$$\Rightarrow 36 $$ days Ans

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