The tops of two poles of height 24 m and 36 m are connected by a wire. If the wire makes an angle of 60 $$^{\circ}$$ with the horizontal, then the length of the wire is
Let's say height of bigger pole is 12+24.
Where length of wire will be hypotenuse, pole length of 12 in bigger pole will be perpendicular and distance between poles will be base.
And angle between base and hypotenuse will be $$\theta$$
Hence length of wire will be = $$12cosec\theta$$ (where $$\theta=60^o$$)
So length of wire will be = $$12 \frac{2}{\sqrt3} = 8\sqrt3$$
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