Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes ?
Distance between buses will $$20\times\frac{10}{60}$$ = $$\frac{10}{3}$$ km.
Now man is travelling this distance in 8 min. with the relative speed of (20+$$x$$) (let's assume speed of man is $$x$$ km/hr )
hence (20+$$x$$) = $$\frac{\frac{10}{3}}{\frac{8}{60}}$$
$$x$$= 5
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