Question 136
The top of a broken tree touches the ground at an angle of 60° and at a distance of 45 m from the base of the tree. The total height of the tree is: (Use $$\sqrt{3}=1.73$$ and $$\sqrt{2}=1.41$$)
Solution
$$tan60°=(height of non broken part/45).$$
So,height of non broken part$$=45√3=77.94$$
So,
$$77.94^2+45^2=height of broken part^2$$
or,$$height of broken part=√8100=90.$$
So, the height of tree$$=77.94+90=167.94.$$
A is correct choice.
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