Question 136

The top of a broken tree touches the ground at an angle of 60° and at a distance of 45 m from the base of the tree. The total height of the tree is: (Use $$\sqrt{3}=1.73$$ and $$\sqrt{2}=1.41$$)

Solution

$$tan60°=(height of non broken part/45).$$

So,height of non broken part$$=45√3=77.94$$

So,

$$77.94^2+45^2=height of broken part^2$$

or,$$height of broken part=√8100=90.$$

So, the height of tree$$=77.94+90=167.94.$$

A is correct choice.

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