PA and PB are two tangents to a circle with centre 0. from a point P outside the circle. A and B are points on the circle. If $$\angle APB=70^\circ$$. then $$\angle OAB$$ is equal to:
$$\angle APB=70°$$
Then $$\angle AOB=110°$$
But triangle AOB is isosceles triangle as
$$AO=BO.$$
So,$$\angle OAB=\angle OBA.$$
So,$$2\angle OAB + \angle AOB=180°$$
or,$$\angle OAB=70/2=35°.$$
B is correct choice.
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