If O be the circumcentre of a triangle PQR and $$\angle{QOR} = 110^o, \angle{OPR} = 25^o$$, then the measure of $$\angle{PRQ}$$ is
As we know circumcentre O is perpendicular bisector of sides of a triangle.
And $$\angle QOR = 110^o$$
and OQ=OR (radius) hence angles OQR and ORQ will be also be equal.
Which will have value equal to $$\frac{180-110}{2} = 35^o$$
Now angle OPR and PRO will also have equal value as $$25^o$$.
So angle PQR will be 35+25 = $$60^o$$
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