SSC CGL 2012 Tier 1 1 July NZ Evening IV

Question 133

If a^3 - b^3 = 56 and a - b = 2, then the value of (a^2 + b^2 + ab) is :

Solution

it is given that $$a^3 - b^3$$ = 56

we know $$a^3 - b^3 = (a-b)(a^2 + b^2 + ab)$$

a- b = 2 (Given)

hence

$$(a^2 + b^2 + ab)$$ = $$\frac{56}{2}$$ = 28

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