Find the value of $$\frac{(243)^\frac{n}{5}\times3^{2n+1}}{9^{n}\times3^{n-1}}$$
Expression : $$\frac{(243)^\frac{n}{5}3^{2n+1}}{9^{n}3^{n-1}}$$
=Â $$\frac{(3^5)^\frac{n}{5}\times3^{2n}\times3}{3^{2n}\times3^{n}\times3^{-1}}$$
= $$\frac{3^{n+2n}\times3}{3^{n+2n}\times3^{-1}}$$
= $$\frac{3^{3n}}{3^{3n}}\times3\times\frac{1}{\frac{1}{3}}$$
= $$3\times3=9$$
=> Ans - (B)
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