Question 132

Find the value of $$\frac{(243)^\frac{n}{5}\times3^{2n+1}}{9^{n}\times3^{n-1}}$$

Solution

Expression : $$\frac{(243)^\frac{n}{5}3^{2n+1}}{9^{n}3^{n-1}}$$

= $$\frac{(3^5)^\frac{n}{5}\times3^{2n}\times3}{3^{2n}\times3^{n}\times3^{-1}}$$

= $$\frac{3^{n+2n}\times3}{3^{n+2n}\times3^{-1}}$$

= $$\frac{3^{3n}}{3^{3n}}\times3\times\frac{1}{\frac{1}{3}}$$

= $$3\times3=9$$

=> Ans - (B)

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