In $$\triangle ABC, \angle A = 50^\circ$$ . In sides $$AB$$ and $$AC$$ are produced to the point $$D$$ and $$E$$. If the bisectors of $$\angle CBD$$ and $$\angle BCE$$  meet at the point $$O$$, then $$\angle BOC$$ is equal to:

A

$$55^\circ$$

B

$$75^\circ$$

C

$$65^\circ$$

D

$$40^\circ$$