ABC is an equilateral triangle and CD is the internal bisector of L C. If DC is produced to E such that AC = CE, then ∠CAE is equal to
As per the problem,
In $$\triangle$$ ACE, AC=CE, thus $$\angle CAE= \angle CEA$$
And $$\angle$$ CAE + $$\angle$$ CEA + $$\angle$$ ACE= 180
so $$\angle$$ CAE= 75
Hence, option B is the correct answer.
Create a FREE account and get: