Question 127

If ΔABC is similar to ΔDEF such that BC = 3 cm, EF = 4 cm and area of ΔABC = 54 $$cm^{2}$$ ,

Solution

Since, ratio of areas of two similar triangles is equal to the ratio of squares of any two corresponding sides.

BC = 3 cm , EF = 4 cm

=> $$\frac{\triangle ABC}{\triangle DEF} = \frac{BC^2}{EF^2}$$

=> $$\frac{54}{\triangle DEF} = \frac{9}{16}$$

=> $$\triangle DEF = \frac{54 * 16}{9} = 96 cm^2$$

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