What is the length (in metres) of the longest rod that can be placed in a room which is 2 metres long, 2 metres broad and 6 metres high?
Length = $$l=2$$ m, Breadth = $$b=2$$ m and Height = $$h=6$$ m
Length (in metres) of the longest rod that can be placed in the room is its diagonals.
=> Diagonal =Â $$d=\sqrt{l^2+b^2+h^2}$$
=> $$d=\sqrt{(2)^2+(2)^2+(6)^2}$$
=> $$d=\sqrt{4+4+36}=\sqrt{44}$$
=> $$d=2\sqrt{11}$$ m
=> Ans - (B)
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