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Question 126
The average mathematics marks of two Sections A and B of Class IX in the annual examination is 74. The average marks of Section A is 77.5 and that of Section B is 70. The ratio of the number of students of Section A and B
Solution
Let's say no of students in section A is N and in section B, it is M
Hence average will be $$\frac{77.5N+70M}{M+N} = 74$$
or 3.5N=4M
or $$\frac{N}{M} = \frac{8}{7}$$
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