If $$x^{2} - y^{2} = 80$$ and x- y= 8, then the average of x and y is
$$x^{2} - y^{2} = 80$$ and $$x - y= 8$$
=> $$x + y = \frac{x^2 - y^2}{x - y} = \frac{80}{8}$$
= 10
$$\therefore$$ Required average = 10/2 = 5
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