Question 124

The ratio of number of males and number of females in village X is 11:7 respectively. If in village Y, the number of males is 20% more than the number of males in village X and the number of females is 12% less than those in village X, then what will be the respective ratio of males to females in village Y ?

Solution

Let the number of males in Village X = $$11x$$

=> Number of females in village X = $$7x$$

=> Males in village Y = $$\frac{120}{100} \times 11x = \frac{66x}{5}$$

=> Females in village Y = $$\frac{88}{100} \times 7x = \frac{154x}{25}$$

$$\therefore$$ Required ratio

= $$(\frac{66x}{5}) : (\frac{154x}{25})$$

= $$3 : \frac{7}{5}$$ = $$15 : 7$$

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