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Question 124
One side of a rhombus is 13 cm and one of its diagonals is 24 cm. What is the area of the rhombus?
Solution
So first we should divide the diagonal
now a $$\triangle\ $$ ABC
the angle is $$90^{\circ\ }$$
now by Pythagoras theorem
(AC)²=(AB)²+(CA)²
now we have AC as 13cm
, AB=12
so it is
(13)²=(12)²+(CA)²
169=144+(CA)²
(CA)²=169-144
(CA)²=25
CA=5cm
so another diagonal =CA×2
=5×2
=10cm
so Area =½×10×24
=120cm²
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