SSC CPO 12th-March-2019-Shift-2

Question 124

One side of a rhombus is 13 cm and one of its diagonals is 24 cm. What is the area of the rhombus?

Solution

So first we should divide the diagonal

now a $$\triangle\ $$ ABC

the angle is $$90^{\circ\ }$$

now by Pythagoras theorem

(AC)²=(AB)²+(CA)²

now we have AC as 13cm

, AB=12

so it is

(13)²=(12)²+(CA)²

169=144+(CA)²

(CA)²=169-144

(CA)²=25

CA=5cm

so another diagonal =CA×2

=5×2

=10cm

so Area =½×10×24

=120cm²


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