Solution
Given : $$ x = \sqrt[3]{7}+3$$
=> $$x-3=\sqrt[3]7$$
Cubing both sides, we get :
=> $$(x-3)^3=(\sqrt[3]7)^3$$
=> $$x^3-27-3(3x)(x-3)=7$$
=> $$x^3-27-9x^2+27x-7=0$$
=> $$x^{3}-9x^{2}+27x-34=0$$
=> Ans - (A)
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