Question 122

The average of three consecutive odd numbers is 12 more than one third of the first of these numbers. What is the last of the three numbers?

Solution

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Let's say numbers are $$a, a+2, a+4$$
So avg. will be $$\frac{(a+a+2+a+4)}{3} = \frac{a}{3} +12$$
Or a = 15
So numbers will be 15, 17, 19

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