Question 122

In ∆ABC, ∟ABC = 70°, ∟BCA = 40°. O is the point of intersection of the perpendicular bisectors of the sides, then the angle LBOC is

Solution

Given : $$\angle$$ABC = 70° and $$\angle$$ACB = 40°

OB and OC are perpendicular bisectors

=> $$\angle$$BOC = 2*$$\angle$$BAC ----------Eqn(1)

In $$\triangle$$ABC

=> $$\angle$$BAC + $$\angle$$ABC + $$\angle$$BCA = 180°

=> $$\angle$$BAC = 180°-(70°+40°) = 180°-110°

=> $$\angle$$BAC = 70°

Using eqn(1), we get :

$$\angle$$BOC = 2*70 = 140°

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