A is 50% as efficient as B. C does half of the work done by A and B together. If C alone does the work in 20 days, then A, B and C together can do the work in
C does $$\frac{1}{20}$$ amount of work in a day.
And A+B do twice of work as much done by C or A+B=2C or $$\frac{2}{20}$$.
So A+B+C together will do $$\frac{2}{20}+\frac{1}{20}=\frac{3}{20}$$ amount of work in a day.
And complete work will be done in $$\frac{20}{3}$$ days.
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