In $$\triangle$$ PQR, the line drawn from the vertex P intersects QR at a point S. If QR = 4.5 cm and SR = 1.5 cm then the ratios of the area of triangle PQS and triangle PSR is
NOTE :- The ratio of area of two triangles on same base is equal to the ratio of two corresponding sides of the two triangles.
Given : QR = 4.5 cm and SR = 1.5 cm
=> QS = QR - SR = 4.5-1.5 = 3 cm
Since, the two triangles PQS and PSR have same base PS
=> $$\frac{area(\triangle PQS)}{area(\triangle PSR)} = \frac{QS}{SR}$$
= $$\frac{3}{1.5}$$ = 2 : 1
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