Question 120

Two circles of same radius 5 cm, intersect each other at A and B. If AB = 8 cm, then the distance between the centres is :

Solution

AB is chord to each of the circle and AB = 8 cm

Radius of each circle = 5 cm

A line drawn from the centre of the circle perpendicular to the chord bisects it in two parts.

=> AC = 8/2 = 4 cm

Now, in $$\triangle$$ OAC

=> $$OC = \sqrt{(OA)^2 - (AC)^2}$$

=> $$OC = \sqrt{25-16} = \sqrt{9}$$

=> OC = 3 cm

=> OO' = 2*3 = 6 cm

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