Let $$|z_{1}-8-2i| \leq 1$$ and $$|z_{2}-2+6i| \leq 2,z_{1},z_{2} \in C$$. Then the minimum value of $$|z_{1}-z_{2}|$$ is :

We need to find the minimum value of $$|z_1 - z_2|$$ given $$|z_1 - 8 - 2i| \leq 1$$ and $$|z_2 - 2 + 6i| \leq 2$$. Here, $$z_1$$ lies in or on the circle centered at $$(8,2)$$ with radius 1, and $$z_2$$ lies in or on the circle centered at $$(2,-6)$$ with radius 2. The distance between these centers is $$d = \sqrt{(8-2)^2 + (2-(-6))^2} = \sqrt{36 + 64} = \sqrt{100} = 10.$$ Therefore, the minimum possible distance between any point in the first circle and any point in the second circle is $$d - 1 - 2 = 10 - 1 - 2 = 7.$$

The correct answer is Option 4: 7.