One third of a certain journey is covered at the speed of 80 km/hr, one fourth of the journey at the speed of 50 km/hr And the rest at the speed of 100 km/hr, what will be the average speed (in km/hr) for the whole journey ?
Let the total distance = $$12x$$ km
Distance covered at 80 km/hr = $$\frac{12x}{3}=4x$$ km
=> Time taken = $$\frac{4x}{80}=\frac{x}{20}$$ hours
Distance covered at 50 km/hr = $$\frac{12x}{4}=3x$$ km
=> Time taken = $$\frac{3x}{50}$$ hours
Distance covered at 100 km/hr = $$12x-4x-3x=5x$$ km
=> Time taken = $$\frac{5x}{100}=\frac{x}{20}$$ hours
Thus, total time = $$\frac{x}{20}+\frac{3x}{50}+\frac{x}{20}$$
= $$\frac{x}{10}+\frac{3x}{50}=\frac{8x}{50}$$
$$\therefore$$ Average speed = total distance/total time
= $$\frac{12x}{\frac{8x}{50}}$$
= $$12\times\frac{50}{8}=75$$ km/hr
=> Ans - (A)
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