A policeman goes after a thief who has 100 metres start, if the policeman runs a kilometre in 8 min, and the thief a km in 10 min, the distance covered by thief before he is over-powered is
given that thief is already 100 m far from police and speed of police is 125 m/min
Speed of thief = 100 m /min
Relative speed of police= 125-100=25 m/min
Using distance = speed x time
100 = 25 × T
T= 4min
In 4 minutes ,thief can cover = 100 × 4 = 400 m
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