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Question 117
A box has 100 blue balls, 50 red balls and 50 black balls. 25% of blue balls and 50% of red balls are taken away. Then, percentage of black balls at present is
Solution
Initially there were 100 blue balls, 50 red balls and 50 black balls.
After taking away there will remain 75 blue balls, 25 red balls and 50 black balls , a total of 150 balls
Hence percentage of black balls will be $$\frac{50\times100}{150}$$ = $$\frac{100}{3}$$
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