Question 116
If the 5-digit number 538xy is divisible by 3, 7 and 11, then the value of $$(x^2 + y^2)$$ is:
Solution
As divisible by 3, 7, 11
means divisible by $$ 3 \times 7 \times 11 $$
$$\Rightarrow 231 $$
then number $$231\times 233 $$
$$\Rightarrow 53823 $$
Hence $$x =2 , y = 3 $$
then $$(x^2 + y^2) = 2^2 + 3^2 $$
$$\Rightarrow 4 + 9 $$
$$\Rightarrow 13 $$ Ans
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