Question 112
Two numbers A and B are such that the sum of 5% of A and 4% of B is 2/3 rd of the sum of 6% of A and 8% of B. The ratio A : B is
Solution
it is given that
$$\frac{5}{100} \times A + \frac{4}{100} \times B$$ = $$\frac{2}{3} \times (\frac{6}{100} \times A +\frac{8}{100} \times B)$$
$$\frac{A}{100}$$ = $$\frac{4B}{300}$$
$$\frac{A}{B}$$ = $$\frac{4}{3}$$
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