Some bricks are arranged in an area measuring 20 cu. m. If the length, breadth and height of each brick is 25 cm, 12.5 cm and 8 cm respectively, then in that pile the number of bricks are (suppose there is no gap in between two bricks)
Let there be 'n' no. of bricks.
Volume of pile=20 $$m^{3}$$
=$$20\times100\times100\times100$$ $$cm^{3}$$
Volume of one brick=$$25\times12.5\times8$$ $$cm^{3}$$
Total volume of pile=Total volume of bricks
$$20\times100\times100\times100=n\times25\times12.5\times8$$
$$n=8000$$
Hence, Option B is correct.
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