Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 111
$$\frac{sec^{2}\theta-\cot^{2}(90^{\circ}-\theta)}{cosec^{2}67^{\circ}-\tan^{2}23^{\circ}}+sin^{2}40^{\circ}+sin^{2}50^{\circ}$$ is equal to
Solution
Expression : $$\frac{sec^{2}\theta-\cot^{2}(90^{\circ}-\theta)}{cosec^{2}67^{\circ}-\tan^{2}23^{\circ}}+sin^{2}40^{\circ}+sin^{2}50^{\circ}$$
= $$\frac{sec^2 \theta - tan^2 \theta}{cosec^2 67 - tan^2 (90 - 67)} + sin^2 40 + sin^2 (90 - 40)$$
= $$\frac{1}{cosec^2 67 - cot^2 67} + sin^2 40 + cos^2 40$$
= $$1 + 1 = 2$$
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
