Sign in
Please select an account to continue using cracku.in
↓ →
ABCD is a cyclic quadrilateral such that AB is a diameter of the circle circumscribing it and angle $$ADC = 130^\circ$$. Then angle BAC is equal to:
Given,
$$ \angle ADC=130^{\circ\ }$$
we know that,
sum of opposite angle of cyclic quadrilateral=$$180^{\circ\ }$$
$$\angle ADC+\angle ABC=180^{\circ\ }$$
$$130^{\circ\ }+\angle ABC=180^{\circ\ }$$
$$\angle ABC=50^{\circ\ }$$
$$In\ \triangle ABC,$$
$$\angle ABC=50^{\circ\ }, \angle BCA=90^{\circ\ }$$
$$\angle BAC=40^{\circ\ }$$
Was this solution helpful?
Create a FREE account and get:
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
