Question 111

A tank 40 m long, 30 m broad and 12 m deep is dug in a field 1000 m long and 30 m wide. By how much will the level of the field rise if the earth dug out of the tank is evenly spread over the field ?

Solution

Length of tank = 40 m

breadth of tank = 30 m

height of tank = 12 m

volume of soil dug out = L x B x H = 40 x 30 x 12 = 14400 $$m^3$$

Area of tank = 40 x 30 = 1200 $$m^2$$

Area of field = 1000 x 30 = 30000 $$m^2$$

Reamaining area = 30000 - 1200 = 28800 $$m^2$$

Height of soil spread if dug out volume of soil is spread on the remaining area = $$\frac{14400}{28800}$$ = 0.5 m

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