Question 110

A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day ?

Solution

lcm of 20,30,60= 60nits

work of A per day = $$\frac{60}{20}$$ = 3

work of B per day = $$\frac{60}{30}$$ = 2

work of C per day = $$\frac{60}{60}$$ = 1

work of A,B,C for 3 day cycle = (3*3)+2+1= 12

days needed to complete the work = $$\frac{60}{12}$$*3 =15 days

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