A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day ?
lcm of 20,30,60= 60nits
work of A per day = $$\frac{60}{20}$$ = 3
work of B per day = $$\frac{60}{30}$$ = 2
work of C per day = $$\frac{60}{60}$$ = 1
work of A,B,C for 3 day cycle = (3*3)+2+1= 12
days needed to complete the work = $$\frac{60}{12}$$*3 =15 days
Create a FREE account and get:
Detailed syllabus & Topic-wise Weightage
By proceeding you agree to create your account
Free CAT Syllabus PDF will be sent to your email address soon !!!
