If 18 binders bind 900 books in 10 days, how many binders will be required to bind 660 books in 12 days ?
As per the given question equation can be written as,
$$ \Rightarrow \frac{900}{10 \times 18}$$ = $$\frac{660}{12 \times x}$$
$$ \Rightarrow 5x = 55$$Â
$$ \Rightarrow x = 11$$
Hence, option D is the correct answer.
Create a FREE account and get:
