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Question 108
A conical flask is full of water. The flask has base radius $$r$$ and height $$h$$. This water is poured into a cylindrical flask of base radius mr. The height of water in the cylindrical flask is
Solution
Volume of water in flask = $$\frac{\pi r^2 h}{3}$$ (where h is height of water in conical flask)
Volume of water in cylinder = $$\pi m^2r^2 h_1$$ (where h_1 is height of water in cylinderical flask)
Hence now $$\frac{\pi r^2 h}{3}$$ = $$\pi m^2r^2 h_1$$
or $$h_1 = \frac{h}{3m^2}$$
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