One pipe fills a water tank three times faster than another pipe. If the two pipes together can fill the empty tank in 36 minutes, then how much time will the slower pipe alone take to fill the tank ?
let's say slower pipe fills tank in $$x$$min. so in 1 min. it fills $$\frac{1}{x}$$
and faster one will fill in $$\frac{x}{3}$$ min. so in 1 min. it fills $$\frac{3}{x}$$
together in 1 min. they will fill ($$\frac{1}{x}$$+$$\frac{3}{x}$$) of tank
as it is given that together they will fill the tank in 36 min.
soÂ
$$(\frac{1}{x}+\frac{3}{x})\times36$$ = 1
or $$x$$ = 144 min.
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