The contractor was engaged to construct a road in 16 days. After working for 12 days with 20 labours it was found that only $$\frac{5}{8}^{th}$$ of the road had been constructed. To complete the work in stipulated the number of extra labours required is:
20 workers will do $$\frac{5}{8}$$ work in 12 days
=>Â Remaining work =Â $$1-\frac{5}{8}$$Â $$=\frac{3}{8}$$
Remaining time = $$16-12=4$$ days
Let number of extra labours required = $$x$$
Using, $$\frac{M_1D_1}{W_1}$$Â $$=\frac{M_2D_2}{W_2}$$
=> $$\frac{20\times12}{\frac{5}{8}}=\frac{(20+x)\times4}{\frac{3}{8}}$$
=> $$20\times12\times3=(20+x)\times4\times5$$
=> $$20+x=36$$
=> $$x=36-20=16$$
=> Ans - (D)
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