If ABCD is a cyclic quadrilateral with $$\angle A$$ = 50$$^{\circ}, \angle B$$ = 80$$^{\circ}$$, then $$\angle C$$ and $$\angle D$$ are

We know that, sum of opposite angles in a cyclic quadrilateral is 180$$^{\circ}$$

$$\therefore \angle A + \angle C$$ = 180$$^{\circ}$$ and $$\angle B + \angle C$$ = 180$$^{\circ}$$

$$\Rightarrow$$ 50$$^{\circ} + \angle C$$ = 190$$^{\circ}$$ (or) $$\angle C$$ = 130$$^{\circ}$$

$$\Rightarrow$$ 80$$^{\circ}+\angle D$$ = 180$$^{\circ}$$ (or) $$\angle D$$ = 100$$^{\circ}$$

Hence, option D is the correct answer.