Solution
Expression : $$f(x) = sin^{2} x + cosec^{2} x$$
= $$(sin x - cosec x)^2 + 2.sin x.cosec x$$
= $$(sin x - cosec x)^2 + 2$$
Since, $$(sin x - cosec x)^2$$ is always positive
=> Min value of f(x) = 2
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