Question 102

If $$f(x) = sin^{2} x + cosec^{2} x$$, then the minimum value of f(x) is

Expression : $$f(x) = sin^{2} x + cosec^{2} x$$

= $$(sin x - cosec x)^2 + 2.sin x.cosec x$$

= $$(sin x - cosec x)^2 + 2$$

Since, $$(sin x - cosec x)^2$$ is always positive

=> Min value of f(x) = 2

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