Question 101

Which of the following is exactly divisible by 6?

Solution

For divisibility by $$6 = 3\times 2 $$

the number must be even and sum of digit must be divisibility = 3   

the check option (A) 4325672 

4+3+2+5+6+7+2 = 29

it is not divisibile by 3

check (B) 5643252 

sum fo given digit 5+6+4+3+2+5+2 = 27 it is divisible by 3 and hence it divisible by also 6

check  option (C)96543111 

sum of given digit  9+6+5+4+3+1+1+1 = 31 it is odd  not divisible by 6

check option (D) 465466 

sum of given digit 4+6+5+4+6+6 = 31 it is not divisible by 6

therefore Only Option (B)5643252 is divisible by 6 

hence Option (C)5643252 Ans 


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