Question 101

The sum of three consecutive natural numbers divisible by 3 is 45. The smallest number is:

Solution

Let the three consecutive natural numbers divisible by 3 be $$(3x-3),(3x),(3x+3)$$

Sum = $$(3x-3)+(3x)+(3x+3)=45$$

=> $$9x=45$$

=> $$x=\frac{45}{9}=5$$

$$\therefore$$ Smallest number = $$3(5)-3=12$$

=> Ans - (C)

Average of the numbers = $$\frac{45}{3}=15$$

Thus, middle number is 15, hence the three numbers must be = 12, 15, 18

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