SSC CPO 11th Dec 2019 Shift-1 Question 10

Question 10

The two given expressions on either side of the ‘=’ sign will have the same value if two numbers on either side or on the same side are interchanged. Find from the given option the correct numbers to be interchanged.
$$4 + 6 \times 2 - 27 \div 3 = 8 \times 2 - 4 + 9 \div 3$$

Solution

Given that expression 

$$4 + 6 \times 2 - 27 \div 3 = 8 \times 2 - 4 + 9 \div 3$$

we check option (A) 6,2 replace to each other 

$$4 + 2 \times 6 - 27 \div 3 =8 \times 6 - 4 + 9 \div 3$$

from the LHS $$4 + 2 \times 6 - 27 \div 3$$

$$\Rightarrow 4 + 12 - 9$$

$$\Rightarrow 16 - 9$$

$$\Rightarrow 7 $$

from RHS$$ 8 \times 6 - 4 + 9 \div 3$$

$$\Rightarrow 48-4+3 = 51-4 = 47 $$

then RHS is not equal to LHS 

then we check option (B)6,8

$$4 + 8 \times 2 - 27 \div 3 = 6 \times 2 - 4 + 9 \div 3$$

then LHS $$4 + 8 \times 2 - 27 \div 3$$

$$\Rightarrow 4 + 8 \times 2 - 9$$

$$\Rightarrow 4 + 16- 9$$

$$\Rightarrow 20- 9 = 11 $$

From RHS $$6 \times 2 - 4 + 9 \div 3$$

$$\Rightarrow 6 \times 2 - 4 + 3$$

$$\Rightarrow 12 - 4 + 3$$

$$\Rightarrow 15- 4  = 11 $$

therefore LHS = RHS then 

option (B) is staisfied the given expression 

Ans (B) 6,8 



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