SSC CHSL 5 March 2018 Evening Shift Question 10

Question 10

If in the population of a town there is an increase of 44% in the first year and 75% in the second year, then what is the average rate of increase in the population?

Solution

Let population of town initially = $$100x$$

Population after 44% increase in 1st year = $$100x+\frac{44}{100}\times100x=144x$$

Population after 75% increase in 2nd year = $$144x+\frac{75}{100}\times144x=252x$$

Thus, rate of increase in population = $$\frac{(252x-100x)}{100x}\times100=152\%$$

=> Average rate of increase in the population in 2 years = $$\frac{152}{2}=76\%$$

=> Ans - (D)



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