Four number-pairs have been given, out of which three are alike in some mannerand oneisdifferent. Select the number-pair thatis different.
In option A,
4 + 5 = 9 = $$3^2$$
In option B,
16 + 20 = 36 = $$6^2$$
In option C,
25 + 41 = 66 $$\ne$$ $$8^2$$
In option D,
30 + 51 = 81 = $$9^2$$
$$\therefore$$ The correct answer is option C.
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